ESZ9-1007-5m-eod 1,2 of 2
6:45 : PP2 ? We need two T1's for that. I can only see one. I don't get why PP2 here. I'd bet on an unvolunteer Ctrl+v here lol
7:05 : I'd see a BMrev too. More like and less like.... ? Well let's discuss this a bit again : at the very first second of the bar it's already out of rtl. The bar in hindsight tells me the close NEVER went inside of the rtl again AND at the very first seconc, very very most likely corresponding volume was below prior level so it was T1. BO on T1. I wonder if the fact that close of price bar did never go insid the rtl expains that the FS you choosed has been only BO,T1.
But the fact is that I don't see how BMrev can be avoided anyway..weird
7:25 : either more BMrev than BO,T1 because... Idk..close was not out of rtl yet when volume exceeded last measured bar ? I wonder.
OR
Omission.
7:35 : both FS's so neither more BMrev nor more BO,T1 than the other one. I can see volume this time is below first P1 so T1 forever along the volume bar unfolded. Maybe that's a clue. Wow, I like all this research !
7:40 : StB on Dec Vol, I don't get why it should be measured.
8:30 : effectively, not more a BMrev than a PP3, nor the reversed option. How did you deal then as for MT ? : prior turn/EE combo was BO,T1/c(D-D)-turn ending set C. Which turn did you choose ? a-turn. Oh !! very super ultra mega interesting !! Cause accordingly to MT, in Set A from BO,T1 as n-1 EE, the linking with BMrev does not exist so it would be a-turn, whereas it does exist with PP3 and it would be then c-turn. You put a-turn, which means :
- you used PP3 as n EE
- the if this is correct, my hypothesis previously exposed consisting in choosing c-turn if possible would be false
AND
a problem remains...PP3 assigns P1 on next measurable bar. In this sequence, next bar is wait, next one is measurable, so it should receive P1...and you put T1.
All happens in this sequence like if you used PP3 as n EE BUT you used BMrev as P1 assign then, on current EE bar. Either a mistake from you or a very high LOD. Of course, I bet on second choice
8:50 : I begin to wonder if putting the numbers for Lats was in fact just a training wheels and scafford as you like saying. They start do appear less and less on your charts.
8:55 : I wonder if the T1 just above retro label on volume pane is for this bar, 8:55 or not. Looks like no, whereas the retro would make it a T1.
AND
once again I do not see BO,T1 being as no rtl can be drawn.
9:50 : ok for BO,T1, applicable on ANY bar, but PP3 ?.. Hhhmm. The bar is not measurable by nature, even though I understand now by reviewing the definition of a failsafe why BO,T1 is there, I can't see the PP3 though.
AND
this case does not help as for which of those two EE's you used as n EE in MT being as from BO,T1 in Set C, both of them lead to c-turn.
9:55 : in any case, here is a confirmation that on two EE's for a bar, if a FS is there you assign P1 on it and not on next bar (in the case the other simultaneous EE is PP!).
10:35 : 6th confirmation for BMrep. I begin to think you place BMrep ASAP and
- remove it if first BM is violated
- lets it if not
10:40 : numbers for Lat ? Scafford ?
11:05 : here for me your extension of the Lat is good while the subLat's is not.
11:10 : first P1 is in a Lat. So it's an INT. PP3 is gated. Second P1 is also in the Lat. If your PP3 is correct, it would confirm my recent DD according to your post as for the "kill" about PP6 which could be extendible to PP3/PP2, that the INT must be a Wait for PP3 to be killed. It's a bit tricky here cause the PP3 bar is not in a Lat, so killed if INT wait (let's say that now), but it's gated if inside a Lat. Anyway, I get it clearly here.
11:15 : 7th confirmation as for BMrep AND first confirmation for, more precisely, the removing action of BMrep if first one is violated. It's what happens here.
11:45 : 8th confirmation as for BMrep placement and removing.
12:55 : the bar 78's treatment looks so easy here. I wonder what PP4a is.
13:00 : 9th confirmation as for BMrep placement and removing.