Finally, I have a very little moment, and as I want to optimize it :
The repeating phrase is your current sticking point. You say you understand this concept but your BM placement and P1 assignment sometimes are congruent to the phrase and at other times not.
Trying to stick to that
Did this bar8 BO of bar7’s T1 associated with the prior BM at bar6?
Yes it does, its close is above prior rtl which was short, so BO,T1, short BM at top being as last one was long at bottom of both bars 6 and 7.
And then, that's how I see what follows :
Bar 8 : XB, BO,T1 of prior established rtl, P1 assigned and as prior BM was long (the repeat one on Bar 7 that creates virtual point 1 of long trend segment which finally appears to be most likely the bar 8 itself) then the new BM is short at top.
Bar 9 : xB, Close is above prior BM, so BM,rev, P1 assigned and new BM long at bottom.
Bar 10 : XB, rtl accelerates, degap required, volume is DEC so T1.
Bar 11 : XB, rtl fans, volume is INC so P2.
Bar 12 : SYM on DEC volume BUT close is out prior rtl so BO,T1, then new short BM at top and vomue OOE resets then P1 assigned on current bar as BO,T1 is FS.
NB : I have a doubt on this one, that comes from "I don't know if the close out of rtl takes precedence on the WAIT action required by SYM + DEC volume". It just makes sense to make start the new short trend segment from this bar.
Bar 13 : XR, volume INC, repeat P1.
Bar 14 : XR, rtl acc, repeat of P1 and there is a NOT PP1 due to absence of accelerating three P1's.
Bar 15 : XR, rtl accelerates, INC volume so P1 repeat and this time PP1 due to acceleration measured. So, next bar is assigned P1 with opposite BM, so BM long at bottom of bar 16.
Bar 16 : XR, rtl accelerates, beginning of a long trend segment underway.
For me, tricky and uncomfort now
Bar 17 : XR, degap required, rtl fans and close is both out of prior rtl AND under prior long BM so -> BO,T1 and BM rev. So P1 assigned on current bar, new opposite BM short at top is drawn.
Until here, I see the long trend segment initiated by low of bar 16 ending at top of bar 17.
Bar 18 : Wait BUT if BO,T1 takes precedence then here BO,T1 of prior rtl and then OOE resets and P1 assigned with long BM.
Bar 19 : XB, rtl fans, volume is DEC so T1.
Comfort is back
Bar 20 : XR, degap required, BO,T1 from prior rtl, OOE resets on FS so P1 assigned and short BM is placed.
Bar 21 : XR, rtl fans, repeat of P1
Bar 22 : XR, degap required, repeat of P1 with acceleration so PP1 EE so OOE resets and P1 is assigned on next bar with associated long BM at bottom.
Bar 23 : XR, rtl fans, degap is required, close BO prior rtl on T1 so BO,T1. BM and P1 was already assigned due to prior EE located.
Uncomfort is back
Bar 24 : racehorse. OB, VTP would say P1/T1 so PP4 EE and assign P1 on next bar, BUT we have here both BMrev AND BO,T1 of prior rtl. So here, I only see a P1 assigned for two FS-reason, so BM short is placed, and due to the nature of OB PC, BM long is also placed at bottom of the bar.
Bar 25 : XR, degap required, rtl accelerates, close crosses prior BM. so BM rev. BUT there were two BMs placed... tricky here. For now, what would make sense for me is just to consider only placing a new short BM short at top, reffering to lastly reversed long BM. It's like a new BM short advancing.
In addition to that, P1 is thus assigned due to FS labelled AND P1 is accelerating and there are 3 in a row. SO -> PP1 EE and next bar is P1 assigned with BM long at bottom.
Comfort is back again
Bar 26 : P1 assigned due to prior PP1 EE, XR, rtl fans
Bar 27 : XR, rtl fans, BM rev so P1 assigned and new BM short placed.
Bar 28 : degap required, FBP after degap, vol DEC so -> WAIT
