Quote from Haroki:
Ok, let's be more specific.
1-The jets provide , say, 100,000 lbs of thrust.
2- it would take, say 40,000 lbs of thrust to roll the jet along on level ground at 150mph (assumed takeoff velocity).
3- so there's 70,000 lbs of thrust that must be counteracted to negate forward movement.
4- the plane's wheels will accelerate to whatever speed necessary to achieve 150mph airspeed.
So what provides the 60,000 lbs of negative thrust against the plane?
X + (conveyor belt speed*y) = (wheel speed * y) + (100,000 lb thrust - 40,000 lb aerodynamic drag)
y = essentially equals zero since the plan'es wheels will accelerate to whatever speed necessary to achieve 150 mph.
So now the equation will be
X = -60,000lbs of thrust.
What provides the negative thrust?
Quote from SuperZtroll:
their wheel has a rotational velocity to it. the very center of the AXIS of the wheel is going nowhere but any point on the wheel OTHER than that is most certainly moving.
i reiterate,
what an idiot !![]()
Quote from Turok:
Haroki:
X + (conveyor belt speed*y) = (wheel speed * y) + (100,000 lb thrust - 40,000 lb aerodynamic drag)
Me:
What is "y" standing in for?
Haroki:
force/lbs of resistance, as provided by the rolling resistance of the tires, etc.
There must be one value for "y" in any single equation. I don't think the rolling resistance of the treadmill itself "(conveyor belt speed*y)" will be the same as the rolling resistance of the wheels "(wheel speed * y)".
However, if you're right and I'm wrong, you should be able to show the work solving the equation for "y". Can you?
JB
Quote from Haroki:
The only resistance that the belt can provide is a source of rolling resistance, normally provided by the asphalt. There is no aerodynamic restance provided, right?
The only interaction between the belt and the tires will be that rolling resistance. Or do you see something else?
What I'm attempting to do is explain that since the belt has no limitations, then neither should the tires, and since the interaction between the 2 will be rolling resistance, then it's logical to make that assumption. Cuz if we start discussing the situation whereby the belt has no limitations, but the plane does, then it becomes a silly one.
Thereby, by that assumption, y=0.
Quote from Turok:
Haroki, your equation makes as much sense as this one ...
Solve for X
X + blue = color of sky + engine thrust
Of course the sky is blue so X = engine thrust. OK, X = engine thrust, so what. All your equation proves is that in fact, you *don't* remember your algebra.
Both sides of an equation must be able to be simplified and in 'here and now' practical terms, "wheel speed" and "engine thrust" can't be simplfied. Mph and Lbs don't mix.
JB