Actually, the hedge does provide a mathematically superior maximum profit! Here's why.
Whether hedging or not the same result is achieve with two entries and two exits. The difference however is that with the hedge, one branch has ZERO risk.
Again, I am working with the assumption that we are trading within a channel. Upper bound U, Lower bound L. C:[L,U] may be rising or falling or neither. Your entry with a short(s) and long(l), E:[s,l] is somewhere in that channel such that, s = -l. ( I think I represented this wrong in my last posting. )
Assume that you enter such that E is falling. Your short will profit along this whole path, s - L. Having achieved L, you exit your short. E:[l] now moves from L to U.
Total maximum profit: s - L + U - L = s + U - 2L (corrected - sorry)
Minimum profit/loss: E:[l].
The same thing can be achieved with a short at E:, and a long at L. However, your short at E: is unprotected. It is only protected if you assume the hedged position E:[s,l].
Unhedged, you assume the risk on both your long and short. Hedged you only assume one risk when you remove the hedge.
There are no additional fees. This is a mistaken believe. In either case, it is a double trade.
Also, while E:[s,l] is travelling to L, you have 100% of your margin available ( atleast, this is true with FXCM ).
Whether hedging or not the same result is achieve with two entries and two exits. The difference however is that with the hedge, one branch has ZERO risk.
Again, I am working with the assumption that we are trading within a channel. Upper bound U, Lower bound L. C:[L,U] may be rising or falling or neither. Your entry with a short(s) and long(l), E:[s,l] is somewhere in that channel such that, s = -l. ( I think I represented this wrong in my last posting. )
Assume that you enter such that E is falling. Your short will profit along this whole path, s - L. Having achieved L, you exit your short. E:[l] now moves from L to U.
Total maximum profit: s - L + U - L = s + U - 2L (corrected - sorry)
Minimum profit/loss: E:[l].
The same thing can be achieved with a short at E:
Unhedged, you assume the risk on both your long and short. Hedged you only assume one risk when you remove the hedge.
There are no additional fees. This is a mistaken believe. In either case, it is a double trade.
Also, while E:[s,l] is travelling to L, you have 100% of your margin available ( atleast, this is true with FXCM ).