cutten
form your perspective is this worth looking at:
1. calc ln(C(t20)/C(t1)) which is the return over the next twenty days. do that for all days. derive a standard deviation of that return.
2. define rangeRange as
ln(max(Ht(0):H(t-20))/min(Lt(0):L(t-20)))
3. calc a rolling EMA on that range = EMA rangeRange
4. set condition
rangeRange < EMA rangerange
and calc 1. under this condition
in other words calc the standard deviation of future returns and try to find filters to increase that standard deviation and thus the likely hood of extreme events = trends over the next period.
?
form your perspective is this worth looking at:
1. calc ln(C(t20)/C(t1)) which is the return over the next twenty days. do that for all days. derive a standard deviation of that return.
2. define rangeRange as
ln(max(Ht(0):H(t-20))/min(Lt(0):L(t-20)))
3. calc a rolling EMA on that range = EMA rangeRange
4. set condition
rangeRange < EMA rangerange
and calc 1. under this condition
in other words calc the standard deviation of future returns and try to find filters to increase that standard deviation and thus the likely hood of extreme events = trends over the next period.
?
