ok, not too sure of the rules you guys are referring to. Haven't played at vegas.
I just started playing craps with the brothers here at the dorms. I have a friend of mine that showed me the rules of the game. 7 or 11 on the first roll you win. 3, 2, and 12 lose on the first roll. The shooter puts down what he wants to bet, and someone matches that is betting against the shooter. If the shooter doesn't hit either of those number, the shooter's goal is to roll the same number (point).
I'm not a math wiz, so my calculations may be incorrect. I wrote down all the possible combinations. I found that 6, 7, and 8 have the same amount of combinations, 3. The way I calculated is this, 1x1, 1x2, 1x3.... 1x6, 2x2. I didn't repeat 2x1 again because of 1x2. I just wanted to know how many combinations are avaiable for each available roll. So basically what I came up with every number other than 6,7,8 have a smaller chance of coming up.
My strategy isn't to bet on the first roll. If the point is either 4, 5, 9, and 10, I would bet against him. If nothing came up, then the odds of a 7 coming up are stronger, so I would up the bet. If the shooter is hot, I wouldn't bet because my strategy works when the shooter isn't hot.
now I've only tried this on two occassions, so I'm gonna keep sticking to my system and hopefully I'll come out ahead. So far so good.
If you guys find my logic incorrect, please feel free to give me your opinions.
thanks,
Andy