Quote from faust:
Fantasy football fans will like this one;
Ticket with two games, Game 1 and Game 2.
Game 1: teams A vs. B with 60/40 slant of team A being the favorite over team B (underdog)
Game 2: teams C vs. D with 50/50 even split to win between C & D
Standard rules, the winning bettors split the total pot.
100 players, each one wagering $1. If you know in advance that 99 other players are betting on team A to win, which game (or team) do you bet on to maximize your returns?
Bon appetite a tout!
If I understand the question correctly you are asking first which game we would like to play, if any, and then which team we would like to put our dollar on.
The way I understand the question, Game 2 will not be played. If you are the only one betting on that game (there are only 100 players with a buck each, you and 99 others), then you pay $1 to flip a coin to see if you get to keep your money.
That is, 50% probability to get back your $1 and 50% probability to lose it. No upside, only downside as all the other money is on the other game.The same if you play Team A in Game 1 you have 60% probability to get back your dollar. (100 players which all put in $1 with a total prize pool of $100). Only downside here too.
If you play Team B in Game 1, on the other hand, you pay $1 to get a 40% probability to win $99. This is the only option with any upside potential, so this would be the only option I would ever even consider. Even though the odds are stacked against you you get a hefty prize relative to the cost of playing, if you get lucky.

Then again, if you don't like to gamble, if you are far over in the risk averse corner (which I don't think many of us in here are), just keep your dollar and wait for the next best thing to come along. A dollar saved is a dollar earned.

