Quote from workwithus:
I have the same EE's up to the OB bar on bar 8 where i don't see jack assigning an upper and lower volume element on bar 8.Here's how i would see that band A creation.Bar 4 is start after BO T1 and assigned a P1.Bar 5 is repeat so another P1.Bar 6 is T1.You now have your upper and lower limits for a band A (see attached post with lite blue in volume pane).Bar 7 is at first a Wait but because of Retro (on the 4th bar of a lateral go back and assign elements) you would assign bar 7 a P2 in hindsight.(I am still working thru pre and post lateral Retro rules but for now it appears once you have the 4th bar of the lateral just go back and ignore any waits plus test and assign the bars per the volume OOE's.This may result in EE's).Bar 8 is an OB and with Retro the upper level would be assigned per the volume test procedures.Since during the creation of the band A the P2 is less than the P1 the "zone" for the T2P is between the T1 and P2.My volume numbers for the T1 bar 6 are 18.2k (rounded) and for the P2 on bar 7 they're 18.4k(rounded).This results in a very narrow range for the T2P "zone".On bar 8 volume lands inside this range at 18.3k(rounded) resulting in the upper level assignment of T2P.Since there is no EE or failsafe triggers (at least that i can tell) i assign the lower level the Next element in the volume OOE's.That would be the T2F.Now i have the T2P/T2F which triggers a PP5a EE.Since the next "level" to be assigned is on the next bar (another OB) i reset the OOE sequence and assign it a P1 (on upper level) on bar 9. I then assign the Next element (T1) to the lower level on bar 9 and this results in a PP4 EE.So i reset the OOE sequence again and assign the P1 to bar 10. http://screencast.com/t/jelJcyg1MHr
Thank you for your reply. I don't believe we follow the OB procedure for the RETRO because the case of Bar 8 is Lat 3 already, and RETRO doesn't call for a re-assignment of cases within the lateral, just a test for the volume element.
I believe this is why we don't see two elements annotated for Bar 8 on Jack's Chart either. Because of this, I have Bar 8 as T2P, Bar 9 as a re-assignment of P2, and Bar 10 as LVBO Ab because the bar is less than T1. Does this make sense or have you seen examples or text that may indicate otherwise?