DD time.
1-the major clue to gettting EE's is to know he band in effect for the bar you are measuring..
This echoes to when JH stated that context is a very powerful tool. We know there are 10 types of EE’s : FS’s, PP !s, A/B/C/F/G/H/J/K-bands’. This sentence, for me, reminds us that to be able to ID a given EE, except for FS that can happen on ANY bar as written on the corresponding sheet, we must know which band is in effect. There are 7 bands and one pre-band. As we know, the only constant thing is change. So we know exceptions are the rule. The true is not the truth. Nor is the false. Instead, we know the true and the false are just moments of the truth, being the synthetical and dialectical result of the relationship between the true and the false, talking with each other, and making surge at last, the truth. Truth is the superior synthetic unit made up of true and false. The truth is the totality. True and false are parts of it. And as we know, the whole is superior to the parts sum. Effectively, the links, the relation is what is missing and what makes the whole superior to sum of parts. Relation is everything. That’s why to know a thing one must know all what is it not, and that’s also why one can know a thing by knowing all what it is not. Context is what matters most. To ID an EE, the truth of an EE, one must know which space, zone, BAND is at hand. Context is everything.
2-P1 and T1 define A band top and bottom repsctively. P2 could be in or out of A band. A geomtric trend is established by P2.
My understanding of this, to be more precise is that first P1 and first T1 are the boundaries of A-band. If repeat P1 or T1 happens, A-band remains samely bounded. And then, after T1 if the trend continues, one can only have either Wait, T1 or P2. Nothing else can happen. Logic and OOE rule. P2 can exceed P1 used for A-band high boundary, and then we have P2 out of A-band. Or we can have P1 >P2, and then P2 is inside A-band. This last described situation prevents some EEs, for instance AgVEBO, to happen. And finally, P2 is an RDBMS item and it corresponds to SCT’s pt2 of the parallelogram. Moreover, T2P gives the slope of rtl of the container.
We know then that unless the trend has progressed until P2, A-band is not there and so no A-band EE can be IDd being as the context for that is not present. AND we know there are exceptions to what has just been said. Let’s go deeper now. After a T1, we know only wait, T1 or P2 can happen if the trend continues. At the first second of development of the bar, it must surely be a T1, whether the current price case allows to measure volume or not. It would be by nature a T1. Any measurable bar is measured, but not all measurabe bars are measured for the traditional permission. After the bar exceeds T1, we have P2. We still state the trend segment continues. At this moment, P2 is there. The bar will end being a P2. I know we need P2 to be established for A-band to become active and for then allow A-band EE’s to be IDd. I had been wondering if, if after the bar passes by the state of P2 at very first time it exceeds T1, the P2 exceeds P1 it would be a revchron. I have cleared this up by DD that if this was true, P2>P1 could not exist, neither could be all EEs requiring P2 >P1. So, once for all, this bar would be a P2. Either ending at >P1 or not. But P2 in any case. So it’s only and only if P2 is at lock in there, that one can after this bar have an A-band EE. BUT, once again, exception rules : Ac-1, Ac-2, Ae-1 for instance. Maybe so is Ah, but I’m not sure at the moment.
3-B band comes into effect with the advent of T2P. See crosshatched zone.
Here is the pic :
View attachment 212931
It is said that B-band comes in effect with the advent of T2P. Comes in effect. What does this mean ?for me it means B-band becomes active and gives an additional context to A-band which is already there, being as A-band requires P2 which is a pre-req to have T2P being as according to the VERS first T2P appear after P2, only after P2. I also know some A-band EE’s are what prevent T2P to surge. It’s logical, being as T2P would be putting B-band in effect. When B-band is there, A-band remains active still. Again, I had been wondering : at the first second, after a P2, that the bar overpasses T1 level it is a T2P. For me, there is a differenciation here to carry out. We have said P2 can be either above or below P1, cause it has been stated P2 can be in or A-band and this band is bounded by P1 and T1. Clear so far.
Now, what about the fourth bar of the trend if P2<P1. So easy..If the fourth bar of the trend after a P1-T1-P2 sequence, reaches an above T1 level, it becomes a T2P right away. What is it until this ID ? It was an AbLVBO cause AbLVBO is described as a bar less than T1 and it is an A-band EE so we need this band to be still there, so this means either A-band or A-band AND B-band to be there for getting permission to see this (any) A-band EE. Ok. Until this fourth bar reaches T1, it is AbLVBO. Then is exceeds AbLVBO zone, and enters into its T2P zone. By definition, T2P is defined as a bar being after P2 AND between P2 and T1. Clear. After the bar is finally not an Ab but a T2P instead, it can exceed P2 which, in this case, is less than P1. If it does not, then at lock in it will be a T2P and B-band will be here active. If it does exceed P2, it enters first in a new zone which is bounded by upper level P1 and lower level P2. What would this bar be then ? A bar following a P2, being superior to it and less than last P1. In this case it’s even more easy cause we only work with a unique P1. So in this zone, this a bar following a P2, that is above it AND less than last P1 : this perfectly fits the definition of a P2 repeat. And then, it can continue its path until exceeding last measured P1, first P1 in this example. What would this bar be then ? A bar, following a P2, being above P1 which is the upper boundary of A-band. It is by nature an HVBO of the band. But does it satisfy any A-band EE ? Here there is a caveat for me. The EE that comes to my mind here, I mean the one this situation makes me think about the most is AgVEBO. BUT I know we need P2>P1 for that. We’re in the case it is not, so Ag VEBO is killed. Nonetheless, there is still an another EE that whispers to my ear « I’m close ». It’s Aa HVBO. What is the description of Aa ? Here it is :
We did the easier ones. Whats left is caveat land.
A four bar gets built. It cannot be simple and straight forward. If it is then the next bar takes you to other bands or is just a new P1
BUT if the four bar contains an internal (wait) somewhere along thel ine, the four bar is primed for ending.
A four bar including a wait is a HVBO Aa if a HVBO comes along.Aa HVBO is an HVBO coming along with a four bar. A four bar. It is P1-T1-P2-T2P. Can’t be anything else for me. According to the handwritten version of A-band sheet, « P1, T1, P2 and T2P are present in the trend ». Once again, the caveat is here for me : we said the bar unfolds after P2<P1 and then exceeds P1 and then becomes a P1revchron AND a HVBO. If there is a Wait, not an INT, a WAIT so half of the class of INT’s, this bar would look like a Aa for me because along the path of the bar, T2P level has been there so T2P has been there. What I wonder is, is this enough and correct to declare T2P is there and then see AaHVBO ? Again, by DD and with the following great formulation by Sprout, it is possible to DD the truth : « if your comprehension of ___ was correct, then ___ would not exist ». I will use this way of reasoning to solve some issues I can feel. It is the same logical way, the same method as used in any Sudoku, or Einstein’s enigma.
So, if it’s true that this bar would be a AaHVBO (with a wait of course, we don’t forget this necessary detail), would this prevent some item that I know they exist, to be ? Yes, it would make P1revchron alone, with no EE, impossible to surge when P2<P1 (yes, we’re in still in this case). But would P1revchron be prevented to happen if P2>P1 ? this is a non-question, being as if P2>P1, the bar we’re talking about would then be an AgVEBO except if we’re in a Lat. Then, the P1revchron would only happen in a Lat AND if Sprout’s assertion that Af HVBO needs P2<P1 is true, then P1revchron could not happen even in a Lat if P2 <P1. There is nothing in the litterature nor in the sheets tending or explicitely saying it is so. Therefore, my DD is that : is the bar exceeds P1, it is only a P1revchron, so there is no AaHVBO so there is no way one could consider the T2P IS there. It must be T2P at lock in and THEN AFTER this bar, one could see Aa for example.
Now, what about the fourth bar of the trend if P2>P1. Easy now thanks to prior DD. Until T1, the bar is AbLVBO. Once exceeding T1 and remaining below P1, yes P1, not P2, P1, the bar is necessarily below P2 being as P2>P1, so it is T2P. And now, what if the bar exceeds P1 and remains under P2 ? Caveat again : I’ve seen Sprout recently ID this bar as T2P. If this was true, would this prevent an item to surge ? We are with P2>P1. Unless we’re in a Lat on this fourth bar, the AgVEBO is gated and so is Ad (but this Ad can be in a Lat, according to the sheet there is no kill for Ad). We are talking about a bar after P2 with P2>P1 and this bar is below P2 at the moment, which would be then the highest value of the sequence. It is a bar between P2 and T1 right after P2. It does satisfy the definition of the T2P. But is it something else ?again, it is a bar after P2 being above P1. So it is by nature also a HVBO. It exceeds P1, upper A-band’s boundary. It is an HVBO. Can a P1 follow a P2 ? from littérature yes, and it must exceed prior P1 for that. It is the case here. So, is it a T2P or a P1revchron ? seems like the two can be. But we know there is only one possible volume ID and we must use the rather ___ than ___, or more like ___ and less like ___. If this bar was a T2P, this would prevent a P1revchron to surge after P2 if P2>P1 AND as long as the bar remains below P2. I don’t see anything in the text nor in the sheets nor from my DD that could do so. Is it more a T2P than a P1revchron ? For me it is more a P1 revchron and less a T2P, cause I see T2P killed if it is above P1 cause by being above P1 it becomes an HVBO. And is there any HVBO being an EE of the A-band when P2>P1 and when this HVBO is just after P2 ? Unless we’d be in a Lat, I see AgVEBO here. If T2P was true on this bar, this would yield to be obliged to have the bar above P2 (which is already above P1) to ID it as AgVEBO. Ow ….ow ….ow….. HVBO ? …..Ag HVBO ? …no, VEBO. Why a different name ? AHA ??????? VEBO !!!!!!!!!! volatility expansion. What does this remind ? VE. When LFT is exceeded. Hum…..Ag VEBO..Why VEBO and not HVBO. Well, I think I get it know. This VEBO surely means higher than HVBO. HVBO means above P1. If VEBO meant the same, why the different nomenclature ? Must be a reason. I DD VEBO means higher than HVBO. SO : after a P2>P1, if next bar is between P2 and T1, it is a T2P, and to be a Ag we need the bar (not to be in a Lat and) to exceed P2. Wow… don’t know yet if this DD is wobbly or not, but it clicks into place and makes me feel great. There must be a reason for calling Ag a VEBO and not a HVBO. It seems clearer to me now. HVBO is just above P1. VEBO may be higher than higher than the P1. Higher than higher. Higher is HVBO, so the first higher means above P1. What about the second higher ? we need something to be higher than P1.Lol, for Ag VEBO P2 needs to be higher than P1. Great. If this is true and I feel it is, this will change several things and will yield several re-iD’s on my last session. What a feeling this is to unlock this kind of things.
4-C band is between T2P and T2F. it is shaded in blue.
To arrive until this point, we need a P1-T1-P2-T2P established at lock in and then, a fifth bar begins. The next volume element in the OOE is T2F. In the text and in the VERS we know that T2F is first after T2P, it is less than T2P, it is killed if it is below T1, it is gated after T2P and T2F, a repeat T2F is less than prior T2F and a T2F revchron is less than prior T2F. When T2F is there, C-band comes into view, it is activated so to speak. We also know that, contrarily to B-band that does not kill A-band, C-band when activated does kill both A and B-bands. This means, logically, that once T2F is in the trend, no A-band nor B-band EE can be encountered anymore.
Once again, I must use this Sprout’s ID, and here is the sequence :
View attachment 212932
So we have P1ass-T1-P2-T2P before. This is the four bar context. At lock-in of last bar, which is T2P, B-band and A-band are activated so every A and B-bands EE’s are gated. In addition, the context is also now pragmatically established for T2F to surge and so, for C-band to be activated. The lowest boundary here is T1. It’s the lowest volume level. On this bar, also appears a BO,T1. So P1 will be assigned to this bar no matter which other EE we could find, being as FS takes precedence when simultaneously encountered with any other EE. So far good. The other EE ID dis Fd LVBO. I have already discussed this case in one maybe two posts, but it still remains an issue. In my comment about this sequence, I said that being as at the moment this fifth bar begins to build and the last bar was a T2P, we know both A-band and B-band EE’s are gated. And being as this fifth bar reaches at lock-in a below T1 level, it means this bar never overpassed T1 so it is a bar in a still A-band EEs gated context and that ends under T1. I said for me, from my DDs and according to both the text and the A-band sheet, this bar satisfies the AbLVBO AND it cannot be anything else than either A-band or B-band EE because T2F has not appeared yet. The answer that has been adressed to me by Sprout has been that with this comprehension of T2F is killed if <T1, would lead to have Fd and Hb impossible to be part of the system. Let’s study that.
5-C band pass
The volume value is between T2P and T2F on the next par after the T2P.
I am almost sure there is a typo here. It would not be the first time. Not at all. JH himself makes mistakes on his charts, gave texts being in clear conflict with his nomenclature of some EE’s as written in sheets (PP1b for example). Even more incredible, I’ve seen him stating in a trend, the M1 and M3 are supported by decreasing volume, while M2 is on increasing volume. Yes, he really did say this. Obviously, he was warned that there was an unsussable conflict between this and all he had bee teaching. He finally apologized and confirmed he had bee wrong, and inverted the things. M1 and M3 on a complete Set C trend, are on dominant volume so increasing and M2 is on decreasing volume. In this world of opposite, inverted, symetric, mirror whatever you want, it’s easy and just human to commit this kind of error. No big deal as long as it is corrected.
Ca EE is here being discussed. It’s the only C-band EE. When do we see a C-band EE ? When C-band is active. When does C-band become active ? With the advent of T2F. The text here says to have a Ca, one must find a volume bar between T2P and T2F on the next bar after the T2P. For me, the typo is on the second T2P of the phrase. It must be T2F. It would be non-sense to ID a bar as an EE of a Band with this Band requiring a bar that has not happened yet. This DD is confirmed by Sprout’s ID here :
We can see Ca needed T2F to surge before it, for Ca to be IDd.
So, rephrased, logically, with no typo we have : The volume value is between T2P and T2F on the next bar after the T2F. It is logical to have an EE between those value because we know that after T2F if vol decreases we can have T2F and after T2P if volume increases it can be a T2P repeat. T2F repeat is found if the bar is below T2F. By nature, the repeat of T2P is an increasing volume while a repeat of T2F is a decreasing volume move. So what if volume stands in-between ? The solution is given by Ca.
Ok. Let’s go back now to what must be studied.
When for the bar IDd as FdLVBO, I said that being as :
- T2F appears first after T2P
- T2F is killed is <T1
- The presence of T2P gates A-band EEs
- A bar in a gated A-band EEs context, that is under T1 is an AbLVBO
Then the bar is AbLVBO AND BO,T1 due to close of n-bar being out of prior rtl, and this is what has been said to me :
In how you understand it, if T2F is killed when < T1, then Fd, Hb's would not exist. The measurable volume bar is always one of the 11 volume elements.
In addition is can also be an EE.
For me, in this particular trend segment, as soon as the bar starts building it can be a T2F and then it can transform into other volume elements. If it stops building and is below T1, then as a T2F < T1 then it qualifies as an EE.
Dissection time.
In how you understand it, if T2F is killed when < T1 : I become aware here that T2F is not killed if <T1. This is in perfect contradiction with what is on the VERS. I’m used to contradictions.
if T2F is killed when < T1, then Fd, Hb's would not exist. Again, this way of saying things is powerfully helpful. So what are Fd and Hb ? *
The measurable volume bar is always one of the 11 volume elements. Apparently there are more than 11 volume elements in the littérature. They are P, T1, P2, T2P, T2F, Not T2P, Not T2F, Not Not T2P, Not Not T2F, P2F, P3P, PFP, FPF and PEP. It is 14. I need to DD about this.
*Here is what Jack says about it :
F type EE's
1-Fa, Fb, Fc and Fd
2-Bands A, B and C occur, then aan extreme bar appears.
3-It can be very high of very low.
4-Lets go from least to most in value.
5-Before in the A band an Ab could appear when the bar value was afte P2 and lower than T1. Later after thyee t2P and T2F have apperaed the F context comes into view.
6-Fd is a value lower than T1.
7-Fc is a value lower than T2F.
8-HVBO's can appear as well.
9-If P2> P1, then a volume value just less than P1 is an Fa.
we do not use D and E but they are inside of the Blue.
10-F band is both above and below the shown bands. Four mini zones apply. Once you understand the concept of zones and begin to use them, then they show "context".
1- We learn that Fa, Fb, Fc and Fd are F-band EEs.
2- We learn that to ID a F-band EE, C-band must have occured. Of course And then extreme bar happen. They will be the F-EE’s.
3- We will have either LVBO or HVBO
4- We start with LVBO
5- Yes we can have Ab after P2 if the bar is below T1. We know that. And being as B-band does not go in the below T1 zone and it does not kill A-band EEs, we can also have Ab after T2P if it is less than T1. No B-band EE covers this zone. It must be A-band’s work. AND, second phrase, we learn the F-context comes into view so F-band is activated LATER AFTER the T2P AND T2F HAVE appeared.
6- F dis a F-band EE, so we need F context to be here. What is required for that ? T2F to have appeared and to be LATER AFTER this T2F (and thus after T2P also, obviously).
So this is Fd. Fd LVBO is a volume value after T2F which is below T1. For me, it’s like the Ab of F-band.
Let’s see if , if one considers T2F to be killed if < T1, then F dis killed, and so is Hb. Ow, what is Hb by the way ?
Ha
Hb
H band occurs after the primary band (A band) And the Scondary band (C Band) have occurred and AFTER n+1 testing has occurred in any band where n+1 testing is done (C and K bands)
Ha covers HVBO, above the A and C zones and higher than P2 if P2> P1.Hb is the LVBO below both the A and C bands. Both occur rarely and are there as part of later trending completeness.
So from this text from JH, Hb is a LVBO. It is below A and C bands. What is the low boundary of A-band ? T1. What is the low boudary of C-band ? T2F, because C-band is between T2P and T2F. Can T2F be less than T1 ? From Sprout’s comprehension, yes, from the sheet strictly speaking, no. Let’s study deeper. Hb covers LVBO below both A and C-bands. Although there’s an issue with the T2F killed or not when <T1, we can agree anyway on the fact that Hb will be less than T1 and less than T2F. Less than both A/C-bands’ boundaries. Now, when does H-band come into view ? From the first paragraphe of the quoted text above, we see that H band occurs after the primary band (A band) And the Scondary band (C Band) have occurred and AFTER n+1 testing has occurred in any band where n+1 testing is done (C and K bands). Most likely, there is a typo here on Secondary band. It is not C-band, but B-band. A-band is the first band. B-band exists and comes after it and before C-band. So B-band must be secondary Band, while C-band is the ternary Band. Ok. Clear. So as first step, to see H context coming into view, C-band (so both A and B-bands too) must have appeared. And moreover, H context appears AFTER n+1 testing has occurred in any band where n+1 testing is done (C and K bands). Although I don’t catch/get/understand what this n+1 rule means concretely, I know and it is confirmed in this text, that it is relative to C-band until K-band. K-band is the last one. Basically I know in the nomenclature that n bar always mean present bar, like bar.0. And n+1 can only mean next bar, after current bar. As n+1 test is applied when C-band is there, it must mean the first n+1 test is made on the bar subsequent to T2F, if measurable of course. I’m maybe missing something here. Like more above in this post I DDd that Ag had received a VEBO and not HVB appelation, there was a reason for that, and it’s because HVBO and VEBO are not the same. So that, different names. Here, if there is a n+1 test to be done after C-band and this is not mentionned in previous Bands, it must mean something is to be done from C-band that is not done in prior Bands. At the moment, I don’t get what. In any case, H band comes after C-band AND the n+1 test. My understanding for now, is that H-band comes into view if we have a sequence unfolding until T2F AND we have measured the next bar AND this next bar is still in the OOE. So to speak, it is the n+2 bar with n-bar being T2F. SO what I understand is that H-context comes along on the second bar after first T2F in the sequence.
A lttile drawing to help and expose how I see what I just said.
So I have Fd being after T2F and below T1. This both lines up with the text and the sheet. And I have Hb being possible after the bar being right after T2F (according to my comprehension of the n+1 rule is). Before going further with the attempt on the resolution of « your comprehension of T2F killed if <T1 would make Fd and Hb impossible to be », let’s see what I see incoherent on this drawing :
First, I can see that after T2F, if next bar is in-between the same T2F and T1, there will be an EE. And I can’t differenciate Fc and P3F. Why so ? Fc is in F-context so from what I understand, right after T2F. So to speak, I’d say n+1 is made here. And I know concerning G-band that G : the G band occurs on n+1 tests of the c band.The volume value is less than the T2F and greater than T1. The name P3F is assigned to the bar and this assignment means the trend did not end by having a thrid peak in the OOE of peaks. So G-band occurs ON the n+1. From what I understand, so it is for F-band. So there’s something to differenciate here. At first sight, what jumps to my eyes is that G, alphabetically speaking, is after F. Lol. Could it be that G-band surge before F-band ? I don’t think so. G-band must appear after F-band. What I see here is that my DD leads me to say both F and G-bands happens simultaneously, on n+1 testing.
When talking about the n+1 testing from C-band, what does n refer to ? I think it’s the current bar. Current..compared to what ? To present. So it is the present bar. I DD it must be the present bar beginning C-band. So it is T2F. So the n+1 testing would be bar after T2F. The n+1 bar with being first T2F. Hmm. Back to the beginning, this does not solve anything. Both F and G band occur on the same bar from what I understand. I must be missing something. Let’s go back then to what JH says when it comes to the n+1 test. He states that after a trend continues its progress, several new bands appears for exlclusive consideration as an order of events in bands. They follow the alphabet. So my DD that Bands appears in an alphabetical order was good. Finally, we know that when a T2P occurs, the B-band is in effect. And then, when a T2F appears, the C-band is in effect and the n+1 rule is applied to carry out the EE test on the NEXT BAR AFTER the T2F appears. ON THE NEXT BAR AFTER THE T2F APPEARS. I’d like to put this sentence in police 500, red and bold. Well. It is clear for me now, that the n+1 means test the bar to see if it is an EE, with the given bar being AFTER T2F. I have another confirmatin of this when I remember that Jack said n-1 is a math item for locating events relatively. The event is the NOW or the present is the nth event. And n-1, therefore, is the event BEFORE the PRESENT event. I can DD n+1, more than obviously, is the event AFTER the present event. There is then absolutely no way I could see the n+1 test rule to be anywhere else than on the first bar AFTER T2F.
Furthemore, Jack states in the « butt thread » that after T2F he has a bar too low for being another T2F. This means a bar after T2F that is too low to be a T2F repeat. What is a T2F repeat ? A bar following T2F and that is below it but still above T1. My LOD says currently that this bar would be a T2F repeat. If no kills was from first T2F and a third bar was coming along being once again between second T2F and T1, I’d see PP6a EE. But if after a T2F the bar is below T1, for me it would be a Fd. This is, by the way, what Jack IDd. Good for this.
Moreover, it was asked to Jack to elaborate the n+1 test. He answered that the n+1 is the name for the NEXT bar. In the subfractal (the T2P to T2F space band, so this is the C-band), he said required that the band, once established, be tested on the NEXT bar. True means volume is between or on the line of the band he calls this C-band. False means another name for the volume bar must be determined. He uses P3F for this bar’s false. P3F stands for the fact that the trend is not finished (it has failed to finish) and then there is more to come in the trend. Finally, we learn there is two others n+1. I know C-band involves the n+1 test. I know J-band EE, does not. And I know K-band EE need T2P and T2F to triple in an order or another to be found and this is possible after the n+1 test has been involved in C-band. What I understand is that K-EE’s are band pass EEs. So in this band I don’t see anything tending to make one DD the K-band involves n+1 test. So, there is n+1 done on C-band. Not done on J nor on K-band. Which bands are remaining ? F, G and H. I know from the text that the F-context comes into view after the n+1 test is done on C-band. And I also know there are two others n+1 tests, according to what Jack says, after the C-band’s. So C-band involves n+1 test, and so must do F-band. G and H bands are remining. What is said in the text about thoses bands ?
Concerning G-band, it occurs on n+1 tests of the c band. Once again. It occurs on the n+1 testS, testS, testSS of the C-band. What I understand here is that the n+1 test is done on G-band, so it is the last n+1 test that is to be done. I need confirmation about this. What more do I now about G-band ?G is a value after a specific test on a specifically defined bar. The test is the n+1 bar, so it is one of the three n+1 test, after the first T2F or successive T2F's. The value is between T1 and T2F the voume bar is named P3F if it occurs. Can G-band appear before F-band ? Being as bands appear in an OOE following alphabet, the answer is no. F-band comes into view before G-band. So it not very precise to say G-band is a n+1 test after T2F. To be more precise, I’d say the first n+1 test is made after first T2F, then the second n+1 test concerns the F-band which comes right after C-band so it is one bar after the bar after the first T2F, and the G-band is the third and last n+1 test and is on the the third bar after T2F if the trend can reach this length. This is what I understand. Before going any further, I need to be sure nothing makes H-band involve n+1 test. If it did, it would mean there are 4 n+1 test and I said Jacks’ writtings made me DD clearly there are 3. I’ve already found 3 n+1 tests. For C-band, F-band and G-band. What is said about H-band ? The H band is outside of P1 and T1 after P2t's AND P2F's have occurred. It does not overlap band F. Band F is inside band H always. Well, this is the original quotation and there is some typo to consider here, surely. P2t does not mean anything. Nor does P2F. I think It’s P2 and P3F. So, rephrased and with my correction of the typos it would be : The H band is outside of P1 and T1 after P2 AND P3F have occurred. It does not overlap band F. Band F is inside band H always. What more about H-band ? I know that H band occurs after the primary band (A-band) and the secondary band (C-band, so here I have a contradiction with my DD that the secondary band is B-band) have occured and after n+1 testing has occured in any band where n+1 testing is done (C and Kbands). Ha covers HVBO above the A and C zones and higher than P2 if P2>P1 ; Hb is the LVBO below both the A and C bands.
Well, again, although this text tends to confirm there is no n+1 test that is to be done in H-band, there is, as always, something that triggers a contradiction with something else. I’m refering to and after n+1 testing has occured in any band where n+1 testing is done (C and Kbands). This sentence, as it is written, states C AND K bands involve n+1. This would be, first, 2 n+1 test whereas it has been said by Jack himself that there are THREE n+1 tests. I have to DD that what, in the italic sentence, is in parenthesis is false and was in fact C-through-K bands. Which would not necessarily mean all of the bands between them and them included, involve the n+1 test, but rather that all bands involving n+1 test are between C and K Bands. This way, things would line up and I’d DD that the bands that involve n+1 test are : C, F and G.
So I am with C, F and G-Bands being the ones involving one n1 test, on each of them. I may have derived a bit from the initial problem but is was necessary.
Back to closer to the first issue. A bar, after T2P, which is below T1 at lock in. We have A-band activated until prior bar which was T2P, and so is B-band, due to the presence of T2P, precisely.
I remind that the formulation that is helping me is « the way you understand ___ would make ___ impossible to be ». Once again, I see the bar described as below T1 and after T2P, as AbLVBO. What has been said to me concerning this ?
In how you understand it, if T2F is killed when < T1, then Fd, Hb's would not exist. The measurable volume bar is always one of the 11 volume elements.
Effectively, once one receive the permission to measure volume from price, one will see the corresponding volume bar having either a simple or a double ID, and if a double ID is there, one of them will take precedence. In other words, once measured, a volume bar can either be a volume element, or it can be (a volume element AND an EE). If there is an EE, although it also have a volume element name, the name as written in the log of the volume bar will be either the name of the EE (if this EE is a PP ! or B-through-K-band EE), or it will be a P1ass for any other EE. Ok, good so far. One mor time : the measurable volume bar is always one of the 11 elements. I’ve said before that I must clear things because I’ve seen in the littérature more than 11 volume element, 14 in fact. For now, no big deal. I suspect some the three remaining having double names. I know it is for example, as states the text, the case for Ha and P3P. Anyway, again this is no big deal for now. What is important in what I’m saying now for my DD is that, I know every measurable and so measured bar is always one of the volume elements list, let’s call it this way. Ow…..
Need to wait a sec…
Every measured volume bar MUST have a volume element name, whether it is an EE or not.
So…After T2P, what is this bar, which is under T1 ? DD time :
- Can it be a P1 ? We’ve progressed beyond T2P and P1revchron is killed after T2P AND one needs the bar to be above prior P1 for seeing a new new P1. So, can’t be a P1.
- A T1 ? No way, once P2 onwards, T1 is killed forever.
- A P2 ? same as P1 although P2 is gated after any volume element.
- A T2P ? by nature T2P repeat needs increasing volume compared to prior T2P.
- T2F ? No, T2F is killed if under T1.
- P3P ? P3F ? It needs T2F to be there already. So no.
- PFP, FPF, PEP ? I don’t know what they are. So for now let’s state no.
- Not T2P ? Not T2F ? Not not T2F ? Not Not T2P ? Haven’t work enough on these te be sure it can be one of them or it can’t. So let’s state no for the now.
Then…..It is at first sight, impossible for this bar after T2P being under T1, to be any of the volume elements. But I know the higher dimension rule is that IT MUST BE on of them. It is none of them, butit gotta be one of them..well..This reminds me one thing : when several IDs are true for a given bar, but I know there is one unique combo of price case/volume element(possibly+EE) for each bar. How one must deal with this ? With the « more like___ and less like___ ». This sounds logic to me nowadays, and it’s a quite easy to DD which of the two EEs fits better, especially when a FS is one of the two EE’s. But here, we are in a case where no ID is possible.
OOOOh !
x+y are possible -> clear it with « this one more than this one », so « this one is more true than the other one ».
Then : neither x nor y are possible ->…………
What is required for the bar in question to be a P1 ? higher than P1 and not after T2P. 2 conditions. How many of them are filled ? none. 0/2, 0% of truth.
For T1 ? no P2 must be there, and lower level than T1. 2 conditions, and on the example discussed, only one is satisified. 1/2. 50% of truth.
For P2 ? Above P2 if no other : 1 condition, here 0% of truth.
T2P ? need after T2P and above it, here 50% of truth.
T2F….. T2F is the next volume element by nature after T2P in the OOE. What is required for T2F : after T2P, less than T2P, above T1. 3 conditions. Here, 2/3 satisfied..66% of truth.
So, …..woaw…which, in this falseness situation, is LESS FALSE so MORE TRUE than the others ? T2F !
So ?! It’s more a T2F than anything else, although it is not really a T2F. And in addition it is a LVBO by being < T1. Now, to ID the EE, how to we proceed ? The major clue to get EE’s is to kow which of the bands is in effect. My comprehension is that we’ve saif this bar is rather a T2F, although it is not. By considering it like a T2F, A and B-band are killed. And being as we ID it as T2F C-band is active but we know this band is tested one bar after the T2F. We are at n bar, we are at T2F so C-band is there….without being really here. So it’s neither a A-band, nor a B-band nor a C-band EE. Which EE is it as T2F being under T1 ? My DD is that in this case, the most logical is that I must use the closest, soonest, earliest, first Band in there OOE in which I can find an EE being under T1…Hi Hi F-band. Hi Hi Fd LVBO.
Wow…That was huge.
One can know a thing by knowing what it is not. To know what a thing is, one must know ALL what it is not.
How do we know we're understanding a thing correctly ? -> does your comprehension prevent any existent item from being ?
Negative logic.
Several ID’s ? -> which one is more true
None ID ? -> which one is less false
This was a two-days DD.
I’ll now develop for myself further DD’s from all this, rebuild from scratch my EE’s matrix that will need refinement, study if this way Fb and Hb are possible to be, study the 11 volume elements, and will produce more DD’s on what remains fuzzy AND will begin to log in real-time again after re-logging some of the last sessions I’ve posted, with this new level of understanding.
This message needs refinement, typos corrections, among things
