I'll expose in my next post the most clearly as possible, what I wonder about, and try to go through some DDs.
- on degap
Here is what Jack says about it :
What I understand here, and to me it is clear : when one degaps, one moves n-1 bar and ALL of this bar. What this "ALL" must mean ? I don't see how it could mean anything other than "all the information contained by bar n-1".
Then, in the following situation, if I applicates what I understand to this scenario :
... then bar 2 would be a BMrev.
To help myself with DD, I remember that when I posted this,
, the answer provided had been :
The degapping consideration example with the lateral you have right.
So, I can DD that it fits to my understanding of what Jack says. When one moves prior bar to make its close match next open, then one moves all of this given n-1 bar : can be a BM, the boundary of a LAT* etc.
SO, if one is to move all the info of the bar that is moved, let's take a scenario and deal also with the squish, and merge the two concepts :
It's a more complete and precise scenario of a snippet I have already posted recently.
Bar1 : at this moment we don't know anything about it.
Bar2 : no degap is required. We have a SYM.
Bar 3 : absolutely XB, relatively (degapped) we have XB.
Here begins the ride.
From what I understand, and the goal of this post is to either reconsider/be firmer with some beliefs and knowledges I have, we are to squish prior bar into Bar 1. One more time let's think about the squish. Cambridge dictionnary says : squish =
the act or sound of crushing something that is
soft.
Well.. in our case, when I think about squishing and look at any INT (being as it's INT's we're to squish), I understand that it means "imagine the second bar creating the INT is merged with the first one, and see what it gives".
Let's dissect
- if I squish a SYM, I'll automatically have the first bar left and nothing of the second bar will appear anymore.
- if I squish a FTP or a FBP, it will be the same as when a SYM is squished.
- if I squish a Hitch, same also
- if I squish a StB or a StB, I will this time have only the second bar remaining.
- If I squish a LAT, I'll have again only the first bar remaining.
During the two last MADA sessions, I was wondering : an INT is an INT. There are, in terms of action to operate when they happen, two kinds of INT : those allowing to measure volume, and those preventing to do so.
I wondered : is any of these two kinds of INT to be squished ?
If any INT is to be squished, it means any INT is to be squished...Wait or UL must not matter.
And later, along the MADA routine, as I was giving a glimpse at prior ID's, I noticed I had been inconsistent in that I had sometimes stopped squishing INT because of the presence of a UL INT, or because of the presence, in a LAT, of measured bar (no need here to say again when and why some Lat"x" are measured or not"). This happens when I'm unsure. Sometimes, th markets makes me think "I should see it this way because it fits better", other times it makes me think "no, rather this way". This is inconsistency. I...hate this !lol
Therefore, here is a first zone I want to clear up. Is any INT to be squished, even though it's a UL one.
Let's go deeper : if I squish bar 2 into bar 1, only bar 1 remains. When bar 3 comes, it is then to be, I assume, compared relatively to bar 1... BUT...bar 3 was to be degapped with bar 2. So, logically I'd say:
- there is no gap between bar 1 and 2, so close of bar 2 will remain, reltively to bar 3's open , at the same position.
- then, when bar 3 comes, it is to be degapped to the position of bar 2's close, itself being imagined inside bar 1 and being merged with it. Here, it does not change anything : I'd still have a SYM, whether I do degap or not.
BUT
It can change a lot in function of bar 3's form compared to bar 1's..
SO -> I wonder, in addition to prior wondering, if when squishing, the degap action is still to be done.
For example here :
When bar 2 comes, when one does degap, one obtains a FBP. After squished, Bar 1 only remains. When bar 3 comes, bar 2's close is now 2 ticks below, so the gap is twice the size of what it usually is.
Then, if one degaps bar 3 with bar 2, then by doing so, one will have bar 3's L 1 tick below bar 1's L AND one won't have a LAT anymore...
As I see it, it's very important and radically decisive to be clear with that.
All I can feel, DD and sense from what I take to be sure, and I'm referring here to
@Sprout 's confirmation for my Lat's example when degap makes it all different or not, I would DD what I said in the very last snippet, is true. In other words, the attached "example" snippet, would make one not see a Lat.
Back to the first global example :
Bar 1 :
Bar 2 : degapped, relatively SYM, squished and only bar 1 will be taken into consideration when bar 3 comes
Bar 3 : degapped of 2 ticks downwards, relatively to bar 1 : SYM, squished and bar 1 only will be the reference.
Bar 4 : absolutely we have XR, relatively to bar 1, we have now to go 2 ticks downards cause bar 3 that originally has a 1-tick gap upwards, is now two ticks below, so the degap of bar 4 compared to the close of bar 3 being inside of bar 1 gives us : a SYM. Squished the, only Bar 1 remains and will be the reference.
Bar 5 : and here we are.
OH.... In the past, at this very moment I'm writing this sentence, I would just have done Ctrl+A, suppr.
I realize now in what i'm saying since the beginning of this post, that I'm not moving the n-1 bar, but the n bar for degap !....
Let's post this artefact and rewrite something exposing clearly and properly what I wanted to...