Making JH' SCT and all his material alive

Your ridgidness will lead to problems IMO.
I'll address a few of the items you've mentioned, knowing full well there is likely disagreement amongst peers, or the very least, a "discussion" to ensue.



OB's, IBGS, mis-ID's, and other market events, either independently or combined can create 1-bar or 2-bar OOE. Saying there are 3 bars is not accurate.



Again, too rigid. Particularly with regards to beginning tapes and sub-fractals where bar-by-bar geometric points are determined.

P1, P2, and even P3 annotations "could be" interchanged. As can T1, T2P/F. These "annotations" are not meant as geometric labeling but rather the existence of peaks and troughs as it relates to a specific OOE. The two methods, geometric and RDBMS are complimentary, not one in the same.

Market is open, time to trade.

Good warnings from you, thank you, hope you did it well yesterday
 
Search for ncx's mango post #912 in Iagmahtmoadb thread, it's an excellent summation of the above thought and also gives insight into the not's and not not's.

If you wish to specify something precisely so that it will not be confused with anything else, you would say that it is-what is left over after you have excluded or eliminated everything it is not. A mango is not an orange, a peach, an apricot, a canteloupe and so forth. These are non-mangoes. When you exclude all the things that a mango is not, then what you are left with is the opposite of a non-mango, namely a mango itself. This is called the double negative of a mango and every permanent and impermanent phenomenon can be individually specified by its own double negative.

Effectively, that's a good insight. Thank you very much for pointing this out.
 
Even though A-band uses P1 and T1 as references, it doesn't initiate until P2. Your drawings imply something different. In one way it is an accurate representation, but it also creates an assumption that are like blinders.

This seems clear to me now
 
To refine the idea of B-band killing A-band, it does in the zone that B-band defines. Bands continue to be active until an new band redefines references and/or zones. Understanding the OOE's of OOE's gives insight into this.

To speak to your current sticking point, since T2F has not initiated; an ID using C-band or any band thereafter is not possible, therefore the ID must exist in a prior band still active.

Struggling with that, thinking about it a lot.

To refine the idea of B-band killing A-band, it does in the zone that B-band defines. Bands continue to be active until an new band redefines references and/or zones. Understanding the OOE's of OOE's gives insight into this.

To speak to your current sticking point, since T2F has not initiated; an ID using C-band or any band thereafter is not possible, therefore the ID must exist in a prior band still active.


Here is an illustration of how I understand what you say

Band killing prior band.png
 
Bar 7 is T2P. Actual B-band width is fully established.
Bar 8 is Ab

And this contradicts my understanding inside prior post :

Bar 7 is T2P -> So B-band is still not defining itself, it IS defined. So A-band is not active anymore. So we can only have after that bar, either B's EE, or volume element.
Bar 8 : you state it's Ab. So A-band EE whereas I understand at this moment A-band is killed.

Need to work and refine, I'm missing something or you're wrong. Most likely, I'm missing something.
 
snippet.png

Your image needs the bands refined. T2P coming into being initiates B-band by defining boundaries for reference, A-band is active on that bar as a possible LVBO and HVBO zones where volume would exist on EOB. B-band EE’s do not exist until the n+1 bar from the T2P.

What is between Lvbo and hvbo is a bandpass.

If T2P is true then it is a A-band bandpass. A-band bandpass is not seen nor is it an EE for it is defined as a T2P.


Logically, the presence of a T2P initiates B-band and kills A band.


T2P coming into being initiates B-band AND A-band is active on that bar. Clear.
B-band EE's do not exist until the n+1 bar from T2P = B-band EE's exist from the next bar after T2P.

Logically, the presence of a T2P initiates B-band and kills A-band.

So here :

Band killing prior band.png


I don't see any possibility nor reason why bar 8 could be any of the A-band EE's.
 
Wait is not measurable. There is no T2P at bar 6. The "pragmatic" is a definition of the B-Band ... upper limit is P2, lower limit is T1. P2 is required to create those boundaries. The actual width of B-band is not created until a measurable T2P comes along. In this way, the B-Band is established "pragmatically".

And while it is true that only one band can be in affect for any one EE, once a band has been established it does not disappear previous bands. As bands come into being, MORE EE's become available for use, until the sequence resets. For instance you can have a OB PP! anywhere, or a PP1c even though B-band is "active". Or PP6a even though C-band is "active". Or Ab even though B-band or C-band is active.

Bar 6 is WAIT... no measurement allowed.
Bar 7 is T2P. Actual B-band width is fully established.
Bar 8 is Ab

Finally, the only way of understanding what you state here would be to say :

When B-band is defined and becomes active, it killes A-band IN THE B-BAND ZONE.

It leads me back to that :

bands.png


So, I'd say if Ab is true on bar 8, it could mean : when a given bar begins to be active, it kills the prior ones' activeness ONLY INSIDE THE GIVEN ZONE OF THE NEW APPEARED Band. The non-concerned parts of prior bands' zones by the new band that appeared, would be then remaining active.
 
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So, for the puzzle of EE and its map, here is a classification of my personal feelings concerning IDing any EE. From those I feel comfortable with, through those I see fuzzyness, to finally those I'm afraid of...lol

Gonna make them appear in decreasing obviousness order, with chart snippets

35 EE's from comfortable to hard.png
 
Bands are on or off. Active or not active. They continue to exist and are toggled on/off, based on the development and/or completion of the current bar. Once created, bands do not get "killed" until the volume sequence is reset with assignment, or EE, including FS.

B-band lives INSIDE A-band...
Maybe a simpler way to think about it is that "active" means it is the farthest progress that has been made in the OOE of bands. In this case B-band. But prior bands and EE's in prior bands are still there and available. Existence of B-band (or any band) means it is now POSSIBLE that an EE associated with that band can occur: there is no MUST occur in the context of this discussion. What happens is that as the trend progresses, the number of EE's available increases. No bands are "killed" until the volume sequence is reset with assignment or EE, includes FS.

Bar 8 Ab... if the bar can not travel far enough to reach and at least slightly exceed the lower limit of the B-band, then it can not be a B-band thing and must be something else. What can it be?
 
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