iS THE stock market be

[stock_trad3r]

modeled vian en engery level equation

Such an euqation would look like this:


E(R,L)=(p1+p2)/2*(Dy/Dt)/(Dy/Dt+2)*V

Dy/Dt slope differential

T0 ,T1 time

V=volume between

E(R)=energy on right of the inflec tion point

E(L) energy on left

 

[Equalizer]

Quote from stock_trad3r:

modeled vian en engery level equation

Such an euqation would look like this:

A clear example of the effects of alcohol intoxication on an ET'ers post...

 

[LeonPhelps]

Quote from Equalizer:

A clear example of the effects of alcohol intoxication on an ET'ers post...

How can you messed up all your speeling and syntex and still get that equation right?

How do you know it's EtOH? I vote for X.

 

[macdmaster]

E=MY(_!_)2

 

[makloda]

Quote from stock_trad3r:

modeled vian en engery level equation

Such an euqation would look like this:

hmmm did you hit the bottle after market close?

 

[LeonPhelps]

Quote from macdmaster:

E=MY(_!_)2

So what are you saying? Is that something like "Your mama is so fat that when she hauls ass she has to make two trips" or what?

 

[LeonPhelps]

Quote from makloda:

hmmm did you hit the bottle after market close?

Nope. During market open. Helps the executions go smoother.

 

[makloda]

He posted 06-08-07 01:14 AM

stock_trad3r... I hope you're OK!

 

[Equalizer]

Quote from macdmaster:

E=MY(_!_)2

Hmm, energy is equal to your "genus hugeanus" squared

 

[stock_trad3r]

The equations try to break down the stock market into an easy to quantify numerical value which is its energy level between intervals T0 and T1. If the slope is flat between T0 and T1 no energy is created, and the function M/(M+2) assumes values between 0 and 1 for positive slopes (M).

The energy on the left side of the euqation must be equal to the right side.