Hello,
Suppose you see options on five different stocks, each with a probability in the money of 10%. Can you actually use classical binomial distributions with this information?
If so, then the probability that exactly two of them will land in the money would be:
(5C2)(.1^2)(.9^3) = 7%
Can we really do reasoning like that?
Suppose you see options on five different stocks, each with a probability in the money of 10%. Can you actually use classical binomial distributions with this information?
If so, then the probability that exactly two of them will land in the money would be:
(5C2)(.1^2)(.9^3) = 7%
Can we really do reasoning like that?