Nice logical not, how many here understand what you wrote?Can you explain why? A lot of people don't seem to understand that doing the opposite of a losing strategy != profitable strategy.
Nice logical not, how many here understand what you wrote?Can you explain why? A lot of people don't seem to understand that doing the opposite of a losing strategy != profitable strategy.
Many roads lead to Rome...Effectively op is asking: if opposite of right is wrong then why not opposition of wrong is right.
Simple answer: There are millions of ways to go wrong , but only one way to do it right.....
1+1 is only 2 not 3 or 4 or 5....not 105...
Yep I've tested both of these cases.You will need to know why the strategy is losing money. Fees... slippage...
It could be it's a 50/50 strategy with 50/50 payout but adding fees and slippage makes both ways a losing strategy.
Or you might have tight stops that will get triggered either way, also making both a losing strategy...
You will need to know why the strategy is losing money. Fees... slippage...
It could be it's a 50/50 strategy with 50/50 payout but adding fees and slippage makes both ways a losing strategy.
Or you might have tight stops that will get triggered either way, also making both a losing strategy...
@Moataz Elmasry did you actually backtest a strategy that resulted in this query?
If your strategy is mean-reverting, and that doesn't work... by what ratios doesn't it work? Never? 50/50?
The opposite of mean-reverting is trend-following. So maybe it doesn't work on a certain timeframe, but it does on another.
Although the phrase "the trend is your friend' certainly is thrur, that doesn't mean it always works either.... depending on stoplosses etc. Unfortunately it's not that easy....
I think remark regarding the 'why' still holds.
The reason why you lose is important.
If for example you lose because your stops are hit all the time, the same problem can occur if you take the opposite direction.
So doing the opposite will then always result in the same failure.
Also, can you expand on what you mean by ratios in the mean-reversion context?