Considering the formula for the daily break even as Iv/16 where 16 is Sqrt(252).
This tells us the the 1 day SD and it also tells us where our break even point is.
But the straddle price for a 1 day option is .79*SD move.
This would mean that our break even is not the SD but rather the mean? Can someone clarify this for me?
I looked at the actual break even formula under BS sqrt(2*gamma/theta) and the numbers coming out are much closer to .79*SD rather than the SD. Here is real time example.
SPX = 2824
SPX March22 Straddle = 18.50
IV = 13
Daily $ SD = 13/16 * 2824 = $22.95
Mean Move = $22.95*.79 = 18.15 =~ Straddle Px
Daily $ Break Even (using BS) = sqrt(2 * theta/gamma) = sqrt(7.8/.02) =~ 19.75
On a side note here is a statement from a Bloomberg Presentation.
I thought both paths realize 16% volatility. In my head, scenario 1 we get (16 vol *5)/5 = 16.
In scenario 2, I get
(0*4 + 80)/5 = 16 vol.
This tells us the the 1 day SD and it also tells us where our break even point is.
But the straddle price for a 1 day option is .79*SD move.
This would mean that our break even is not the SD but rather the mean? Can someone clarify this for me?
I looked at the actual break even formula under BS sqrt(2*gamma/theta) and the numbers coming out are much closer to .79*SD rather than the SD. Here is real time example.
SPX = 2824
SPX March22 Straddle = 18.50
IV = 13
Daily $ SD = 13/16 * 2824 = $22.95
Mean Move = $22.95*.79 = 18.15 =~ Straddle Px
Daily $ Break Even (using BS) = sqrt(2 * theta/gamma) = sqrt(7.8/.02) =~ 19.75
On a side note here is a statement from a Bloomberg Presentation.
I thought both paths realize 16% volatility. In my head, scenario 1 we get (16 vol *5)/5 = 16.
In scenario 2, I get
(0*4 + 80)/5 = 16 vol.