New to studying options, in my first read-thru of "McMillan on Options". (A great book, imo, and I agree w/the ET reviews stating this is good stuff to know whether one uses options or not. *Much* to be learnt from this here tome.) My intial interest is to use options as simple risk control. The other book I've read is Kaeppel's "4 Biggest Mistakes...". I understand HV well enough, the volatility of the underlying price movement, and I think I understand that IV, as McM puts it, is the future vol suggested by option prices. IV can also give one a sense of whether options are cheap or dear. OK.
McM cites the case of AMD and Intel in '94, when the latter filed against the former, it goes to trial, and the market awaits the outcome, so HV is low, understandably, since no knows what that outcome will be, but which should result in a good price move in AMD one way or t'other. This would be common sense, but McM says this pov would be furthered by the *high* IV of AMD options, which also makes sense as longs and shorts try to anticipate the outcome of the suit.
Kaeppel says that one of the biggest mistakes that traders make who use options as a substitute for the underlying, just buying calls or puts rather than going long/short the underlying, is to buy higher IV, relative to some timeframe, a year I believe is what he suggests. The reasoning being that the higher IV will probably have limited upside potential, as they are expensive, w/greater downside potential, as IV will cycle, revert to the mean, etc. So the high IV (expensive) option may not move as well w/the underlying (delta, yes?) as will the lower IV (cheap) option.
So in the Mcm example, high IV (and low HV) creates a potentially explosive situation, so the high IV is a positive. But in Kaeppel's example, the high IV is a negative. But they both seem to make sense. Is this seeming contradiction because of the differing circumstances? Still, I'm confused: If one were looking to go long the underlying on a breakout from a trading range, a low HV condition, but substituting buying a call via Kaeppel, then wouldn't a high IV suggest that the market was looking for a strong move?
Thanks,
Harold
McM cites the case of AMD and Intel in '94, when the latter filed against the former, it goes to trial, and the market awaits the outcome, so HV is low, understandably, since no knows what that outcome will be, but which should result in a good price move in AMD one way or t'other. This would be common sense, but McM says this pov would be furthered by the *high* IV of AMD options, which also makes sense as longs and shorts try to anticipate the outcome of the suit.
Kaeppel says that one of the biggest mistakes that traders make who use options as a substitute for the underlying, just buying calls or puts rather than going long/short the underlying, is to buy higher IV, relative to some timeframe, a year I believe is what he suggests. The reasoning being that the higher IV will probably have limited upside potential, as they are expensive, w/greater downside potential, as IV will cycle, revert to the mean, etc. So the high IV (expensive) option may not move as well w/the underlying (delta, yes?) as will the lower IV (cheap) option.
So in the Mcm example, high IV (and low HV) creates a potentially explosive situation, so the high IV is a positive. But in Kaeppel's example, the high IV is a negative. But they both seem to make sense. Is this seeming contradiction because of the differing circumstances? Still, I'm confused: If one were looking to go long the underlying on a breakout from a trading range, a low HV condition, but substituting buying a call via Kaeppel, then wouldn't a high IV suggest that the market was looking for a strong move?
Thanks,
Harold