
Quote from sittingduck:
1- Four cards are dealt off the top of a well shuffled deck. You have a choice:
(a) To win $1 if the first card is a club, and the second a diamond, and the third is a heart, and the fourth is a spade, in this order.
(b) To win $1 if the four cards are of four different suits, in any order.
Which option is better? Or are they equivalent?
Justify by showing what is the probability in each case.

Quote from theboxer:
If you just think about it, it becomes obvious that option B has the better chance (the one where the suits can be in any order). But, if my figuring is correct, then:
The chance of hitting <b>option A</b> is about <b>0.0044</b>
The chance of hitting <b>option B</b> is about <b>0.1082</b>
(also assuming you have a deck with 13 of each suit, i.e. a "straight deck")
Does anyone disagree?