Yea, I was kind of thinking that getting stopped out is a sort of mini-black swan. Because there's no reason to take a trade that isn't profitable. So, getting stopped out is something you didn't expect to happen.
I mean, I don't see the relevancy of something that is supposed to provide transparency to something that is inherently opaque. It just seems to me that L2 provides a false sense of market clarity, when there is none.
I'm just wondering how people manage their trading knowing that at some point a black swan event will occur. I'm thinking something along the lines of:
1) Live in a constant state of fear and trade as if a black swan event could occur at any moment.
2) Never give it a thought, since it would...
What's the incentive to work harder when you're grossly underpaid?
I really don't see what CEO's do that makes their job any more tough than a cashier at McDonald's. Granted, CEO takes more brains and ingenuity, but no more or less of a work ethic.
Why indeed. Thanks, finally "finished." This stupid thing was giving me a headache.
upbars = IIf ( C != O , Sum ( C > O , BarsSince ( O > C ) ) , 0 ) ;
downbars = IIf ( C != O , Sum ( O > C , BarsSince ( C > O ) ) , 0 ) ;
for ( i = 1 ; i < BarCount ; i++ ) {
while ( C[i] > O[i] ) {
upbar = upbar + 1 ;
}
}
Where is the endless loop? It says it's an endless loop, but I just don't see it.
Thanks.
Thanks but, the variable targetprice is in the sell equation. I don't see how that could work.
Maybe this is a better way of framing the question: How do I make the value of a variable independent of the array it's drawn from? Because it keeps updating every refresh. How do I stop it from...
targetprice = Ref ( alt , -BarsSince ( Buy ) ) ;
alt is an array that constantly changes from bar to bar. I want targetprice to reference the specific value of the alt array at the bar when the buy signal occurred. The problem with the above solution, is that if another buy signal occurs...
Hmm...
Figure 13.6 will not run. Line 8 results in Error 52. You have to change fastlength to a value 2 or greater for the script to run.
Figure 17.1 will not run correctly either. The attached picture shows an incorrect output. I've looked at it until I was blue and it has nothing to do...